Optional Calculations for Dwelling Units – Philippine Electrical Code

Optional calculation method applies to a single dwelling unit, whether it is a separate building or located in a multifamily dwelling.

Philippine Electrical Coode, Article 2.20.4 permits optional calculations for feeder and service load calculations for dwelling units.

Conditions for Optional Calculations

This section applies to a dwelling unit if the following conditions are complied with:

  1. The total connected load served by a single 115/230-volt or 208Y/120-volt set of 3-wire service or feeder conductors with an ampacity of 100 or greater.
  2. The general calculated load shall be not less than 100 percent of the first 10 kVA plus 40 percent of the remainder loads
  3. 24VA/sq.m. for general lighting and general-use receptacles.
  4. 1500 VA load for each 20-ampere small-appliance branch circuit and each laundry branch circuit.
  5. Nameplate rating of all appliances that are fastened in place, permanently connected, or located to be on a specific circuit

Sample Calculation

A sample calculation has been provided in the Philippine Electrical Code 2017 Appendix D, Example D1.

Single Family Dwelling Unit, Up to 150 Square Meters Floor Area. (More than Six Circuits)
The dwelling has a floor area of 145 sq. m. It has the typical household appliances including one 8-kW electric range, two 1-Hp room air-conditioning unit, one 1.5-Hp room air-conditioning unit, and one 1-Hp water pump.
Air Conditioning Load: (See Section 2.20.4.3)
Two 1-Hp room air-conditioning unit, 8A x 230 V x 2 = 3680 VA
One 1.5-Hp room air-conditioning unit, 10A x 230 V x 1 = 2300 VA
Other Loads:
General lighting and convenience receptacle load, 145 m² x 24 VA/m² = 3480 VA
One 20-ampere small appliance circuit @ 1500 volt-amperes = 1500 VA
One 20-ampere laundry circuit @ 1500 volt-amperes = 1500 VA
One 8-kW electric range = 8000 VA
One 1-Hp water pump, 8A x 230V = 1840 VA
Total Other Loads: 16320 VA
Application of Demand Factors (Other Loads): [See Section 2.20.4.3(C)]
First 10 000 volt-amperes @ 100% D.F. = 10000 VA
Remainder @ 40% D.F. = (6 320 VA x 0.40) = 2528 VA
Total Net Computed Load = (3680 + 2300 + 10000 + 2528) = 18508 VA
See also  Circuit Breaker Utilization Categories (IEC 60947-2)

Circuit Requirement:

Use eight 20-ampere 2-wire branch circuits and one 40-ampere 2-wire branch circuit.

Service Entrance Conductors:

Total Full Load Current: 18508 volt-amperes / 230V = 80 amperes

Use 2 x 38mm² THW wires.
Note 1: See Section 2.40.1.4 for the conductor and overcurrent protection ampere rating.
Note 2: See Section 2.30.2.3 for minimum service entrance conductor.

Service Equipment:

(A) Maximum Current Rating of Protective Device with (See Section 4.30.4.2 and Table 4.30.4)
(1) Nontime Delay Fuse.
[3 680 VA + 300% (2300 VA) + 10000 VA + 2528 VA] +230 V = 100 Amperes

(2) Inverse Time Circuit Breaker.
[3 680 VA + 250% (2300 VA) + 10000 VA + 2528 VA] +230 V = 95 Amperes

(B) Service Equipment Rating.

Use one 200-ampere, 1PST, 250-volt safety switch with one 125-ampere fuse (renewable); or use one 125-ampere trip, 1-pole, 240-volt molded case circuit breaker (see Section 2.40.1. 6).

Single Line Diagram