Calculations:Transformer Efficiency and Regulation: Difference between revisions
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== Example Calculations == | == Example Calculations == | ||
An example for a typical power transformer. | |||
''Transformer parameters'' | ''Transformer parameters'' | ||
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:Load loss – 9.0 kW | :Load loss – 9.0 kW | ||
Transformer Impedance | '''Transformer Impedance''' | ||
: <math>Z=0.6+j5.97=6.0 \Omega \, </math> | : <math>Z=0.6+j5.97=6.0 \Omega \, </math> | ||
=== Efficiency at 100% load unity power factor === | |||
At unity power factor (full load) | At unity power factor (full load) | ||
: <math> r cos \phi + x sin \phi = 0.6 \times 1 + 5.97 \times 0 = 0.6 \, </math> | : <math> r cos \phi + x sin \phi = 0.6 \times 1 + 5.97 \times 0 = 0.6 \, </math> | ||
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:Voltage Drop<math> = 0.6 + \frac{- 5.97^2}{200} = 0.778\% \, </math> | :Voltage Drop<math> = 0.6 + \frac{- 5.97^2}{200} = 0.778\% \, </math> | ||
'''As per IEC Standard''' | |||
: <math> {\eta}\% = 100-\left(\frac{P_o+n^2 P_k}{n S_n cos \phi \left(1-\frac{U_{ \phi n}}{100} \right) + P_o + n^2 P_k}\right) \times 100 \, </math> | : <math> {\eta}\% = 100-\left(\frac{P_o+n^2 P_k}{n S_n cos \phi \left(1-\frac{U_{ \phi n}}{100} \right) + P_o + n^2 P_k}\right) \times 100 \, </math> | ||
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: <math> {\eta}\% = 100-\left( \frac{11.3}{1499.63} \right) \times 100 \, </math> | : <math> {\eta}\% = 100-\left( \frac{11.3}{1499.63} \right) \times 100 \, </math> | ||
: <math> {\eta}\% = 99.246\% \, </math> | : <math> {\eta}\% = 99.246\% \, </math> | ||
'''As per ANSI Standard''' | |||
At 0.8 power factor (full load) | At 0.8 power factor (full load) |
Revision as of 07:41, 19 September 2023
Transformer Efficiency and Regulation
Introduction
The calculation of efficiency differs from IEC 60076 and ANSI C57.12 Standards because of the difference in defining rated kVA by these standards.
IEC 60076 Standard and ANSI C57.12 Standard
The rated power is defined by IEC 60076 as “When the transformer has rated voltage applied to a primary winding, and rated current flows through the terminals of a secondary winding the trans- former receives the relevant rated power for that pair of windings”.
This implies that it is a value of apparent power input to the transformer, including its own absorption of active and reactive power. The apparent power that the transformer delivers to the circuit connected to the terminals of the secondary winding under rated loading differs from the rated power. The voltage across the secondary terminals differs from the rated voltage by the voltage drop (or rise) in the transformer.
This is different from the definition as per ANSI C57.12.00 standard, where the rated kVA is defined as
The rated kVA of a transformer shall be the output that can be delivered for the time specified at rated secondary voltage and rated frequency without exceeding the specified temperature rise limitations under prescribed conditions of test, and within the limitations of established standards.
Calculation as per ANSI Standard
The efficiency of a transformer is the ratio of its useful power output to its total power input.
where
- efficiency (%)
- output
- input
- losses
For power factor of "S" and load of "x" per unit, the formula for efficiency is
where
- efficiency (%)
- no-load loss (W)
- load loss at full load at reference temperature (W)
- per unit load
- power factor per unit
The calculation of efficiency differs from IEC 60076 and ANSI C57.12 Standards because of the difference in defining rated kVA by these standards.
Calculation as per IEC Standard
The voltage drop (or rise) of the transformer secondary will have to be considered, while the efficiency is calculated, as per IEC standard.
where
- efficiency (%)
- no-load loss (kW)
- (kVA)
- load loss (kW)
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {cos \phi} = \, } power factor
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {U_{\phi n}} = \, } voltage drop (or rise) %
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {U_{ \phi n}} = n \times \left(r cos \phi + x sin \phi \right) + \frac{\left[ n \times \left(r sin \phi - x cos \phi \right) \right]^2}{200} \, }
Example Calculations
An example for a typical power transformer.
Transformer parameters
- kVA – 1500
- Voltage ratio – 11/0.433
- % Impedance – 6.0
- % Resistance – 0.6
- % Reactance – 5.97
- No-load loss – 2.3 kW
- Load loss – 9.0 kW
Transformer Impedance
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Z=0.6+j5.97=6.0 \Omega \, }
Efficiency at 100% load unity power factor
At unity power factor (full load)
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r cos \phi + x sin \phi = 0.6 \times 1 + 5.97 \times 0 = 0.6 \, }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r sin \phi - x sin \phi = 0.6 \times 0 - 5.97 \times 1 = -5.97 \, }
- Voltage DropFailed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = 0.6 + \frac{- 5.97^2}{200} = 0.778\% \, }
As per IEC Standard
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {\eta}\% = 100-\left(\frac{P_o+n^2 P_k}{n S_n cos \phi \left(1-\frac{U_{ \phi n}}{100} \right) + P_o + n^2 P_k}\right) \times 100 \, }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {\eta}\% = 100-\left(\frac{2.3+9.0}{1500 \times 1 \left(1-\frac{0.778}{100} \right) + 2.3 + 9.0}\right) \times 100 \, }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {\eta}\% = 100-\left( \frac{11.3}{1499.63} \right) \times 100 \, }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle {\eta}\% = 99.246\% \, }
As per ANSI Standard
At 0.8 power factor (full load)
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r cos \phi + x sin \phi = 0.6 \times 0.8 + 5.97 \times 0.6 = 4.062 \, }
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle r sin \phi - x sin \phi = 0.6 \times 0.6 - 5.97 \times 0.8 = -4.416 \, }
- Voltage DropFailed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = 4.062 + \frac{- 4.416^2}{200} = 4.159\% \, }
At unity power factor (50% load)
- Voltage DropFailed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = 0.5 \times 0.6 + \frac{(- 5.97 \times 0.5)^2}{200} = 0.3445\% \, }
At 0.8 power factor (50% load)
- Voltage DropFailed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = 0.5 \times 4.062 + \frac{(- 4.416 \times 0.5)^2}{200} = 2.055\% \, }